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VERY IMPORTANT INFORMATION FOR NUMBER 1
PLEASE REMEMBER TO USE YOUR SCHOOL'S AVERAGE TITRE VALUE(AVERAGE VOLUME OF ACID). WE USED 21.47cm3, TRY TO KNOW YOUR SCHOOL'S AVERAGE TITRE VALUE. ASK YOUR CHEMISTRY TEACHER. THEN, ANYWHERE YOU SEE 21.47cm3 IN MY CALCULATION, PUT YOUR SCHOOL'S OWN AND RE-CALCULATE. THIS IS VERY IMPORTANT!!!
(1)
Volume of pipette is 25.00cm³
Titrations |Rough| 1 | 2 | 3
Final Reading|23.00|21.50|21.40|21.50
Initial Reading|0.00|0.00|0.00|0.00
Vol. Of acid used|23.00|21.50|21.40|21.50
(1a)
Vol of acid used VA = 21.50+21.40+21.50/3
= 21.47cm³
(1bi)
Conc. Of A in g/dm³ = 3.65÷500/1000 = 7.3g/dm³
Conc. of A in mol/dm³ = gram conc/molar mass
= 7.3/[1+35.5] = 7.3/36.5
=0.2mol/dm³
(1bii)
Using CAVA/CBVB = nA/nB
0.2×21.47/CB×25.00 = 2/1
CB = 0.2×21.47/25.00×2
= 0.08588mol/dm³
(1biii)
Molar mass of B = gram conc/molarity = 10.60/0.08588
=123.43g/mol
(1biv)
X2CO3 = 123
2[X] + 12 + 3[16] = 123
2x + 60 = 123
2x = 123 - 60 = 63
X = 63/2 = 31.5
(1bV)
No of moles of X2CO3 = molarity × volume
= 0.08588 × 25
= 2.147moles
Mole ratio of X2CO3 to CO2 is 1:1
Therefore, No of moles of CO2 released = 2.147moles
Volume of CO2 released = 2.147 × 22.4
=48.1dm³
CLICK HERE FOR THE IMAGE
CLICK HERE FOR THE IMAGE
(2ai)
Tabulate:
TEST: C + 5cm³ of distilled water and shake thoroughly. Divide the solutions into three portions.
OBSERVATION: A pale green solution results
INFERENCE: Salt is soluble
(2aii)
TEST: To the first portion add NaOH solution in drys
OBSERVATION: Dark green gelatinous was formed
INFERENCE: Fe²+ present
(2aiii)
TEST: then in excess
OBSERVATION: Precipitate is insoluble
INFERENCE: Fe²+ present
(2aiv)
TEST: To the second portion add K3Fe(CN)6 solution
OBSERVATION: A dark blue precipitate formed
INFERENCE: Fe²+ confirmed
(2bi)
TEST: To the third portion add AgNO³ solution
OBSERVATION: White Precipitate formed
INFERENCE: SO4²- , CL- CO²- present
(2bii)
TEST: To the results obtained in add dilute HNO3 in drops , then excess
OBSERVATION: White Precipitate is insoluble
INFERENCE: CL- present
(2biii)
TEST: To the results obtained in add NH3 solution
OBSERVATION: White Precipitate dissolves
INFERENCE: CL- Confirmed
(3)
CLICK HERE FOR THE IMAGE
CHEMISTRY PRACTICAL QUESTIONS 👇
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0039.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0036.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0035.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0022.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0023.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0032.jpg)
NECO CHEMISTRY PRACTICAL QUESTION & ANSWER SOLUTION - 2020 EXPO RUNZ
![NECO 2020 Chemistry Expo Answer](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgFNuyhBVOU3k_toXm3ElAf1o-RYvD1VdpB-vpsRDWTMzVb9YtKlfNqSa7-zLZnEj1iuThMWs4c7yNqZpEYuntI90aovYJZMX1I0h-c4S3H8kq8SVXivvOJyL0owIU1eWo99qYmUTLcK0k/s1600/neco-1.jpg)
PLEASE REMEMBER TO USE YOUR SCHOOL'S AVERAGE TITRE VALUE(AVERAGE VOLUME OF ACID). WE USED 21.47cm3, TRY TO KNOW YOUR SCHOOL'S AVERAGE TITRE VALUE. ASK YOUR CHEMISTRY TEACHER. THEN, ANYWHERE YOU SEE 21.47cm3 IN MY CALCULATION, PUT YOUR SCHOOL'S OWN AND RE-CALCULATE. THIS IS VERY IMPORTANT!!!
(1)
Volume of pipette is 25.00cm³
Titrations |Rough| 1 | 2 | 3
Final Reading|23.00|21.50|21.40|21.50
Initial Reading|0.00|0.00|0.00|0.00
Vol. Of acid used|23.00|21.50|21.40|21.50
(1a)
Vol of acid used VA = 21.50+21.40+21.50/3
= 21.47cm³
(1bi)
Conc. Of A in g/dm³ = 3.65÷500/1000 = 7.3g/dm³
Conc. of A in mol/dm³ = gram conc/molar mass
= 7.3/[1+35.5] = 7.3/36.5
=0.2mol/dm³
(1bii)
Using CAVA/CBVB = nA/nB
0.2×21.47/CB×25.00 = 2/1
CB = 0.2×21.47/25.00×2
= 0.08588mol/dm³
(1biii)
Molar mass of B = gram conc/molarity = 10.60/0.08588
=123.43g/mol
(1biv)
X2CO3 = 123
2[X] + 12 + 3[16] = 123
2x + 60 = 123
2x = 123 - 60 = 63
X = 63/2 = 31.5
(1bV)
No of moles of X2CO3 = molarity × volume
= 0.08588 × 25
= 2.147moles
Mole ratio of X2CO3 to CO2 is 1:1
Therefore, No of moles of CO2 released = 2.147moles
Volume of CO2 released = 2.147 × 22.4
=48.1dm³
CLICK HERE FOR THE IMAGE
CLICK HERE FOR THE IMAGE
(2ai)
Tabulate:
TEST: C + 5cm³ of distilled water and shake thoroughly. Divide the solutions into three portions.
OBSERVATION: A pale green solution results
INFERENCE: Salt is soluble
(2aii)
TEST: To the first portion add NaOH solution in drys
OBSERVATION: Dark green gelatinous was formed
INFERENCE: Fe²+ present
(2aiii)
TEST: then in excess
OBSERVATION: Precipitate is insoluble
INFERENCE: Fe²+ present
(2aiv)
TEST: To the second portion add K3Fe(CN)6 solution
OBSERVATION: A dark blue precipitate formed
INFERENCE: Fe²+ confirmed
(2bi)
TEST: To the third portion add AgNO³ solution
OBSERVATION: White Precipitate formed
INFERENCE: SO4²- , CL- CO²- present
(2bii)
TEST: To the results obtained in add dilute HNO3 in drops , then excess
OBSERVATION: White Precipitate is insoluble
INFERENCE: CL- present
(2biii)
TEST: To the results obtained in add NH3 solution
OBSERVATION: White Precipitate dissolves
INFERENCE: CL- Confirmed
(3)
CLICK HERE FOR THE IMAGE
COMPLETED - GOODLUCK
CHEMISTRY PRACTICAL QUESTIONS 👇
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0039.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0036.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0035.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0022.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0023.jpg)
![](https://expotab.me/uvw/uploads/IMG-20201021-WA0032.jpg)
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